IGCSE Physics revision · Mechanics
Momentum
An Extended-paper topic built on one conservation law. Collision calculations look intimidating but follow a single fixed recipe: total momentum before equals total momentum after.
Dr Desouky Physics Academy · Meet your physics tutor
What the syllabus demands
- —Define momentum as mass × velocity and calculate it
- —Define impulse as force × time and relate it to the change in momentum
- —Apply the principle of conservation of momentum to collisions in one line
- —Explain safety features (crumple zones, airbags) using impulse
Definitions that earn marks
Clear definitions to practise — check your course mark scheme
- Momentum
- The product of mass and velocity: p = mv. A vector quantity, measured in kg m/s.
- Impulse
- The product of force and the time for which it acts: impulse = Ft = change in momentum (Δp).
- Principle of conservation of momentum
- When two or more bodies interact, the total momentum before the interaction equals the total momentum after, provided no external forces act.
The equations
More equations to practise: the IGCSE formula sheet.
Where the marks die
Common mistakes to check
- 01
Ignoring direction. Momentum is a vector: choose a positive direction, and give anything moving the other way a negative velocity before you add.
- 02
Forgetting that objects moving together after a collision share one velocity — the combined mass (m₁ + m₂) multiplies the single final velocity.
- 03
Explaining airbags with 'they absorb the impact'. The physics: they increase the time over which the momentum changes, so for the same change in momentum the force is smaller (F = Δp ÷ t).
- 04
Quoting momentum in newtons. The unit is kg m/s (or the equivalent N s).
One worked example, done properly
Question
A 2.0 kg trolley moving at 3.0 m/s collides with a stationary 1.0 kg trolley and they stick together. Calculate their common velocity after the collision.
Method
- 1.Total momentum before = (2.0 × 3.0) + (1.0 × 0) = 6.0 kg m/s.
- 2.After: momentum = (2.0 + 1.0) × v = 3.0v.
- 3.Conservation: 3.0v = 6.0, so v = 2.0.
v = 2.0 m/s in the original direction