IGCSE Physics revision

IGCSE Physics revision · Mechanics

Moments and turning effects

A short topic with one equation and one principle, commonly tested through calculations. The marks are often lost in the distances: they must be perpendicular, and they must be measured from the pivot.

Dr Desouky Physics Academy · Meet your physics tutor

What the syllabus demands

  • Define the moment of a force and calculate it
  • Apply the principle of moments to balanced beams and levers
  • Describe an experiment to verify the principle of moments
  • Define centre of gravity and describe how to find it for a plane lamina
  • Relate the position of the centre of gravity to stability

Definitions that earn marks

Clear definitions to practise — check your course mark scheme

Moment of a force
The turning effect of a force: moment = force × perpendicular distance from the pivot.
Principle of moments
For an object in equilibrium, the sum of clockwise moments about any point equals the sum of anticlockwise moments about that point.
Centre of gravity
The point through which the whole weight of an object appears to act.
Equilibrium
The state in which there is no resultant force and no resultant moment on an object.

The equations

MomentM = F × d · N md = perpendicular distance from pivot
Balance conditionF₁ × d₁ = F₂ × d₂

More equations to practise: the IGCSE formula sheet.

Where the marks die

Common mistakes to check

  1. 01

    Measuring distances from the wrong point. Every distance in a moments calculation is measured from the pivot — not from the end of the beam, not from the other force.

  2. 02

    Forgetting the weight of the beam itself in Extended questions. A uniform beam's weight acts at its centre — include it as a force at the midpoint.

  3. 03

    Defining equilibrium with only 'no resultant force'. Full marks require both: no resultant force and no resultant moment.

  4. 04

    Mixing units — a distance given in centimetres is fine as long as every distance is in centimetres. Consistency, not conversion, is what matters here.

One worked example, done properly

Question

A uniform seesaw is pivoted at its centre. A child of weight 400 N sits 1.5 m from the pivot. Where must a 600 N adult sit to balance it?

Method

  1. 1.Balance: clockwise moment = anticlockwise moment.
  2. 2.400 × 1.5 = 600 × d.
  3. 3.d = 600 ÷ 600 = 1.0 m.

d = 1.0 m from the pivot, on the other side

Fit these topics into your free physics revision plan

Common questions

Asked, answered.

How do you find the centre of gravity of a lamina?

Hang the lamina freely from a pin, hang a plumb line from the same pin, and draw the vertical line. Repeat from a second point. The centre of gravity is where the lines cross. This experiment appears repeatedly on Paper 6.

What makes an object stable?

A low centre of gravity and a wide base. The object topples when the vertical line through its centre of gravity falls outside the base.

What are the two conditions for equilibrium?

The resultant force on the object is zero, and the resultant moment about any point is zero. Both statements are required for the definition marks.

Find your physics class

Your next chapter starts with one message.

Tell Dr Desouky your level, exam board and city. Choose in-person physics lessons in Abu Dhabi or live online lessons across the UAE and Gulf.

Ask about physics lessons

AED 150 · 90-minute live online session

Contact Dr Desouky for in-person availability, location and fees.