The key idea
Distinguish the amount of matter from the gravitational force acting on it, then connect mass and volume through density. Measurement methods and unit conversions are as important as choosing the equation.
Understand it · 01
Ask whether the quantity is matter or force
A balance gives a mass reading, usually in grams or kilograms. Weight is the gravitational force on that mass, measured in newtons. Moving an object from Earth to the Moon does not remove any of its matter, but the weaker gravitational field produces a smaller weight. The relationship W = mg connects the two quantities; it does not make them interchangeable.
Convert grams to kilograms before multiplying by a gravitational field strength in newtons per kilogram. Use the value of g stated in the problem, which may be rounded. The same g can be expressed as a free-fall acceleration in metres per second squared: both units are consistent with F = ma. Weight acts towards the attracting body's centre, not in a universal direction called down throughout space.
Understand it · 02
Choose a volume method that matches the object
For a regular block, measure its mass and its three perpendicular dimensions. Multiply length, width and height to obtain the volume, using consistent units. A repeated measurement of each dimension can help identify variation. The density calculation compares the mass with this entire volume; dividing by one length or by a face area would calculate a different quantity.
An irregular non-porous object can displace water instead. Record the initial cylinder reading, fully submerge the object and record the new reading. The increase is the object's volume. Remove attached air bubbles and make sure the object fits without spilling water. If it absorbs water or dissolves, this method changes the sample and is unsuitable. A floating object also needs a modified method because partial immersion does not displace its full volume.
Understand it · 03
Make the mass and volume refer to the same sample
To measure a liquid's density, first find the mass of the empty container, then the mass with the chosen volume of liquid. Subtract to obtain the liquid's mass alone. A balance's tare function performs this subtraction, but the volume must still be read separately. Including the container mass overestimates the density because you divide extra mass by only the liquid's volume.
Grams per cubic centimetre and kilograms per cubic metre are both valid density units. Converting 1 g to 0.001 kg and 1 cm³ to 0.000001 m³ shows that 1 g/cm³ equals 1000 kg/m³. Keep one consistent unit system through the calculation, then convert the final density if requested. Water near room temperature has a density of about 1 g/cm³, which is a useful order-of-magnitude check.
Understand it · 04
Floating depends on average density and displaced fluid
A floating object at rest has an upward buoyant force balancing its weight. As more of it is submerged, it displaces more liquid and the buoyant force increases. If the object's average density is less than the liquid's density, balance can occur while part of the object is still above the surface. The liquid's density matters: the same object may sink in one liquid and float in another.
A hollow metal boat can float even though the metal itself is denser than water. Its mass is spread over a large external volume that includes enclosed air, so its average density can be below water's. If water floods that space, the total mass increases without a comparable increase in external volume. Avoid explanations based only on being light: size, volume and the displaced liquid are essential to the comparison.
Key definitions
- Mass
- A measure of the quantity of matter in an object; measured in kilograms and unchanged by location.
- Weight
- The gravitational force acting on an object; W = mg, measured in newtons, and different on different planets.
- Density
- Mass per unit volume; ρ = m ÷ V.
- Gravitational field strength (g)
- The force per unit mass acting on an object in a gravitational field; g = 9.8 N/kg near the Earth's surface.
Equations, units & conditions
Weight
W = m × g
Units: N
Density
ρ = m ÷ V
Units: kg/m³ or g/cm³
Worked examples, step by step
Example 1
A stone of mass 135 g is lowered into a measuring cylinder containing 60 cm³ of water. The level rises to 110 cm³. Calculate the density of the stone.
Follow the method
- Volume of stone = 110 − 60 = 50 cm³ (the displacement).
- ρ = m ÷ V = 135 ÷ 50.
ρ = 2.7 g/cm³ (= 2700 kg/m³)
Practice questions with worked solutions
Try each question on paper before opening the solution. These are original academy questions; the suggested marks are a self-checking guide, not an official exam-board mark scheme. Difficulty labels describe this practice set, not predicted grades.
Build · 4 suggested marks
1. Remove the container mass
An empty measuring cylinder has mass 52 g. It has mass 148 g when holding 120 cm³ of a liquid. Calculate the liquid density in g/cm³ and kg/m³.
Show solution and self-check: question 1
- Liquid mass = 148 − 52 = 96 g.
- Density = 96/120 = 0.80 g/cm³.
- Multiply by 1000 to convert to kg/m³.
Density = 0.80 g/cm³ = 800 kg/m³.
Self-check · one mark per point
- Subtracts the cylinder mass.
- Uses mass divided by liquid volume.
- Finds 0.80 g/cm³.
- Converts to 800 kg/m³.
Stretch · 4 suggested marks
2. Connect volume, mass and weight
A block measures 5.0 cm × 4.0 cm × 3.0 cm and has density 2.5 g/cm³. Calculate its mass in kilograms and its weight where g = 10 N/kg.
Show solution and self-check: question 2
- Volume = 5.0 × 4.0 × 3.0 = 60 cm³.
- Mass = density × volume = 2.5 × 60 = 150 g = 0.150 kg.
- Weight = mg = 0.150 × 10 = 1.5 N.
Mass = 0.150 kg; weight = 1.5 N.
Self-check · one mark per point
- Finds volume 60 cm³.
- Multiplies by density to find 150 g.
- Converts to 0.150 kg.
- Finds weight 1.5 N.
Common mistakes & how to avoid them
- Saying an astronaut's mass changes on the Moon. Mass is the same everywhere; only weight changes, because g changes.
- Mixing density units: 1 g/cm³ = 1000 kg/m³. If the mass is in grams and the volume in cm³, do not convert to kg and m³ separately mid-calculation.
- In the displacement method, forgetting that the volume of the object equals the rise in water level — final reading minus initial reading, not the final reading alone.
- Explaining floating only with 'it is light'. Compare the object's average density with the liquid's density and describe how buoyancy balances weight when it floats at rest.
Understand the why
Questions, explained
Start with the short answer, then follow the reasoning. Each explanation has a permanent link you can share with a classmate or return to when revising.
What is the difference between mass and weight in IGCSE physics?
Mass measures the amount of matter in an object and is measured in kilograms. Weight is the gravitational force on that mass and is measured in newtons. For the same object, mass stays unchanged when location changes, while weight changes with gravitational field strength through W = mg.
An astronaut does not lose matter merely by travelling to a world with weaker gravity. A gravitational force sensor would show a different reading there because it responds to force. Everyday speech often uses weight for a mass in kilograms, but an exam calculation needs the quantities and their units separated.
The value of g is force per kilogram when used in W = mg. Convert the mass to kilograms before multiplying by g in N/kg. A zero support-force reading during free fall also does not prove that gravity has disappeared: the object can still have gravitational weight while no surface is supporting it.
Same mass in different fields
A 2.4 kg instrument is taken from a place where g = 10 N/kg to one where g = 1.6 N/kg. Calculate its weight in each place.
- First weight = 2.4 × 10 = 24 N.
- Second weight = 2.4 × 1.6 = 3.84 N.
- The mass remains 2.4 kg in both locations.
Weights: 24 N and 3.84 N. Mass: 2.4 kg in each place.
How do you find the density of an irregular object?
Measure its mass, then determine its volume by water displacement if it is non-porous, fully submerges and does not dissolve. Subtract the initial water reading from the final reading and divide mass by that displaced volume. Remove attached bubbles before recording the final level.
The cylinder's final reading contains both the original water volume and the newly displaced volume. Using that final reading directly would overestimate the object's volume and underestimate density. Lower the object gently, keep all of it below the surface and avoid losing water over the cylinder's edge.
Select a different approach if immersion changes the sample. A porous material can absorb liquid, a soluble solid can disappear into it, and a floating object displaces only part of its own external volume when left freely at the surface. State the suitability conditions instead of describing displacement as a universal method for every irregular object.
Find the displaced volume first
A non-porous sample has mass 96 g. Water rises from 38 cm³ to 70 cm³ when it is fully submerged. Find its density.
- Sample volume = 70 − 38 = 32 cm³.
- Density = 96/32 = 3.0 g/cm³.
Density = 3.0 g/cm³ = 3000 kg/m³.
Why does ice float on water?
Ordinary ice is less dense than liquid water, so it can displace water equal to its own weight before it is fully submerged. The upward buoyant force then balances its weight. Floating is therefore a density and force-balance effect, not simply evidence that ice is light.
Freezing water forms a structure that occupies a larger volume for approximately the same mass. Dividing that mass by a larger volume gives a smaller density. The individual water molecules have not become larger, and the change should not be explained as water acquiring extra mass on freezing.
If a piece of ice is pushed farther below the surface and released, it displaces more water than required for balance and experiences an upward resultant force. It rises until enough of its volume is above water for the forces to balance again. The density comparison must always identify the surrounding liquid, since changing that liquid can change whether an object floats.
How do I convert density from g/cm³ to kg/m³?
Multiply a density in g/cm³ by 1000 to obtain kg/m³. A gram becomes 0.001 kilogram, but a cubic centimetre becomes 0.000001 cubic metre; dividing those conversion factors gives 1000. To convert kg/m³ back to g/cm³, divide by 1000.
Density contains a mass unit above a volume unit, so both must be converted. Converting only grams would make the numerical value smaller and give the wrong unit combination. The much larger number of cubic centimetres inside one cubic metre more than offsets the mass conversion.
You can often leave a calculation in g/cm³ until the final step if both mass and volume were measured in those units. Converting every input first is valid too, but creates more powers of ten to track. Water near room temperature is about 1 g/cm³ or 1000 kg/m³, giving a useful check on the direction of conversion.
Convert a measured material density
Express 7.2 g/cm³ in kg/m³, and 850 kg/m³ in g/cm³.
- 7.2 × 1000 = 7200 kg/m³.
- 850/1000 = 0.850 g/cm³.
7.2 g/cm³ = 7200 kg/m³; 850 kg/m³ = 0.850 g/cm³.
Why must I subtract the container's mass when measuring liquid density?
Density must use the mass and volume of the same material. A filled container's mass includes the container as well as the liquid, while the cylinder reading gives only liquid volume. Subtracting the empty container mass isolates the liquid mass and prevents an overestimated density.
A balance's tare function can perform this subtraction before the liquid is added. Place the empty, dry container on the balance, zero the reading and then add the sample. If the container changes between the empty and filled measurements, the subtraction no longer represents just the liquid you intended to measure.
Keep liquid on the outside of the container out of the measurement: it adds mass but is not included in the cylinder's internal volume reading. Read the meniscus correctly and make sure the mass and volume refer to the same quantity of liquid, rather than weighing one portion and reading the volume of another.
Avoid including the beaker
A container has mass 40 g when empty and 120 g with 100 cm³ of liquid. Find the density and the incorrect value obtained without subtraction.
- Liquid mass = 120 − 40 = 80 g.
- Correct density = 80/100 = 0.80 g/cm³.
- Using the filled mass gives 120/100 = 1.20 g/cm³, which is too large.
Correct density = 0.80 g/cm³; including the container would give 1.20 g/cm³.
How can a steel ship float if solid steel sinks?
A ship's hollow hull encloses a large volume of air, so its total mass can be small enough relative to the volume it displaces for buoyancy to balance weight. Compare the average density of the complete floating object with water, not just the density of steel.
A compact steel block has little external volume for its mass. Even when fully submerged, the buoyant force from the displaced water may be smaller than its weight, so it sinks. Forming steel into a hollow watertight hull changes the volume available to displace water without requiring a proportional increase in mass.
Adding cargo makes the vessel sit lower because more displaced water is needed to balance the larger weight. Flooding can fill the previously air-filled volume with water and remove the benefit of that hollow space. The explanation depends on a watertight shape and adequate displaced volume; it does not mean every metal object with an air pocket must float safely.
Your learning checklist
Use these goals to check your understanding. Requirements vary by specification, tier and exam year; the official references below define your full course.
- Distinguish mass (amount of matter) from weight (gravitational force)
- Use W = mg with g = 9.8 N/kg (or 10 N/kg)
- Define density and calculate it for regular solids, irregular solids and liquids
- Describe the displacement method for the volume of an irregular object
- Predict floating and sinking by comparing densities
Sources & how to cite these notes
Original explanations, illustrations and practice by Dr Desouky Physics Academy. Official specifications guide the course scope; questions and suggested marks on this page are our own revision material.
- Cambridge IGCSE Physics 0625 — 2026–2028 syllabus
- Pearson Edexcel International GCSE Physics 4PH1 — specification
Reference this page
Dr Desouky Physics Academy. IGCSE Physics: Mass, weight and density. Updated 2026-09-25. https://www.drdesouky.com/revision/igcse-physics/mass-weight-and-density
Use the arrow beside an explanation heading to link straight to that section. Spotted a problem? Contact the academy with the topic and the step you want us to check.