IGCSE Physics revision · Mechanics
Mass, weight and density
Three quantities students think they know from everyday life — which is exactly why the definitions cost marks. In physics, mass and weight are different things, and exam questions test that distinction frequently.
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What the syllabus demands
- —Distinguish mass (amount of matter) from weight (gravitational force)
- —Use W = mg with g = 9.8 N/kg (or 10 N/kg)
- —Define density and calculate it for regular solids, irregular solids and liquids
- —Describe the displacement method for the volume of an irregular object
- —Predict floating and sinking by comparing densities
Definitions that earn marks
Clear definitions to practise — check your course mark scheme
- Mass
- A measure of the quantity of matter in an object; measured in kilograms and unchanged by location.
- Weight
- The gravitational force acting on an object; W = mg, measured in newtons, and different on different planets.
- Density
- Mass per unit volume; ρ = m ÷ V.
- Gravitational field strength (g)
- The force per unit mass acting on an object in a gravitational field; g = 9.8 N/kg near the Earth's surface.
The equations
More equations to practise: the IGCSE formula sheet.
Where the marks die
Common mistakes to check
- 01
Saying an astronaut's mass changes on the Moon. Mass is the same everywhere; only weight changes, because g changes.
- 02
Mixing density units: 1 g/cm³ = 1000 kg/m³. If the mass is in grams and the volume in cm³, do not convert to kg and m³ separately mid-calculation.
- 03
In the displacement method, forgetting that the volume of the object equals the rise in water level — final reading minus initial reading, not the final reading alone.
- 04
Explaining floating with 'it is light'. The mark scheme wants a density comparison: the object floats because its density is less than the density of the liquid.
One worked example, done properly
Question
A stone of mass 135 g is lowered into a measuring cylinder containing 60 cm³ of water. The level rises to 110 cm³. Calculate the density of the stone.
Method
- 1.Volume of stone = 110 − 60 = 50 cm³ (the displacement).
- 2.ρ = m ÷ V = 135 ÷ 50.
ρ = 2.7 g/cm³ (= 2700 kg/m³)