The key idea
Distinguish the motor effect, where a current in an external magnetic field experiences a force, from induction, where a changing linked magnetic field produces an e.m.f. Use that distinction to explain motors, generators and transformers.
Understand it · 01
Determine a current’s magnetic field
A current in a straight wire produces a magnetic field in circles around the wire. Use the right-hand grip rule: point the thumb in the direction of conventional current, and the curled fingers give the field direction. Conventional current is opposite to the direction electrons drift in a metal. Reversing the current reverses the circular field direction, while increasing current strengthens the field for the same geometry.
A solenoid combines the fields of many turns into a pattern similar to a bar magnet. Inside a long solenoid, away from its ends, the field is comparatively uniform. Curl the right-hand fingers in the current direction around the turns; the thumb points towards the solenoid’s north pole. A soft-iron core can strengthen the field, but it is not what creates the original field: the current does.
Understand it · 02
Explain a force on a current-carrying conductor
A wire carrying current across an external magnetic field can experience a force. This motor effect connects electricity to motion. The force direction is perpendicular to both the current and the field, and can be found using Fleming’s left-hand rule when required. Reversing either the current or the field reverses the force; reversing both leaves the force direction unchanged.
In a simple d.c. motor, opposite sides of a coil experience forces in opposite directions, producing a turning effect. A split-ring commutator reverses the current in the coil every half-turn so that the turning effect continues in the same rotational direction. Increasing current or field strength can increase the turning effect, but heating, friction and practical construction affect a real motor’s performance.
Understand it · 03
Identify the change that produces an induced e.m.f.
An e.m.f. is induced when the magnetic field linked with a conductor or coil changes. Moving a magnet towards a coil, moving a wire across a field, or changing the current in a neighbouring coil can produce this change. Holding a magnet stationary relative to an otherwise unchanged coil does not keep producing an induced e.m.f. A closed conducting path is needed for the induced e.m.f. to drive a current.
Faster relative motion, a stronger magnet or more turns can produce a larger induced e.m.f. in a comparable setup. Reversing the motion reverses its direction. Lenz’s law describes a direction that opposes the change causing it, consistent with energy conservation: a generator needs mechanical work supplied to keep transferring energy electrically. It does not create useful energy from nothing merely because a magnet is present.
Understand it · 04
Use transformer ratios with their assumptions
An alternating current in a transformer’s primary coil produces a changing magnetic field in the core. This links the secondary coil and induces an alternating e.m.f. A steady direct current cannot maintain this process after switching transients. For an ideal transformer, Vp/Vs = Np/Ns. More secondary turns give a larger secondary voltage, but do not multiply the available power.
If losses are neglected, input power equals output power: VpIp = VsIs. A step-up transformer therefore reduces the current associated with the same transmitted power. Smaller current reduces heating losses I²R in transmission cables. Real transformers lose energy through heating and other processes, so their output power is lower than their input power. State the ideal assumption whenever you equate the two powers.
Key definitions
- Electromagnetic induction
- An e.m.f. is induced across a conductor when it moves relative to a magnetic field and cuts field lines, or when the magnetic field through it changes.
- Motor effect
- A current-carrying conductor in a magnetic field experiences a force, provided the current is not parallel to the field.
- Transformer
- Two coils wound on a soft-iron core: an alternating current in the primary produces a changing magnetic field in the core, which induces an alternating e.m.f. in the secondary.
Equations, units & conditions
Transformer equation
Vp ÷ Vs = Np ÷ Ns
Ideal transformer power
Vp × Ip = Vs × Is
Worked examples, step by step
Example 1
A transformer has 400 turns on the primary and 20 turns on the secondary. The primary is connected to a 240 V a.c. supply. Calculate the secondary voltage.
Follow the method
- Vp/Vs = Np/Ns, so 240 ÷ Vs = 400 ÷ 20 = 20.
- Vs = 240 ÷ 20.
Vs = 12 V (a step-down transformer)
Practice questions with worked solutions
Try each question on paper before opening the solution. These are original academy questions; the suggested marks are a self-checking guide, not an official exam-board mark scheme. Difficulty labels describe this practice set, not predicted grades.
Starter · 3 suggested marks
1. Use a transformer ratio
An ideal transformer has 900 primary turns and 150 secondary turns. Its primary voltage is 240 V. Calculate the secondary voltage and identify whether it steps up or down.
Show solution and self-check: question 1
- Vs/Vp = Ns/Np.
- Vs = 240 × 150/900 = 40 V.
- The secondary voltage is lower than the primary.
40 V; a step-down transformer.
Self-check · one mark per point
- Use the turns-to-voltage ratio correctly.
- Calculate 40 V.
- Identify step-down operation.
Build · 4 suggested marks
2. Predict an induction signal
A student pushes a magnet into a coil connected to a centre-zero meter, holds it still, then pulls it out. Describe the meter observations, assuming a complete circuit.
Show solution and self-check: question 2
- During insertion, the changing linked field induces an e.m.f. and current, so the meter deflects.
- While stationary, the linked field is unchanged and the meter returns to zero.
- During withdrawal, the change reverses and the meter deflects in the opposite direction.
- Faster motion gives a greater deflection in otherwise comparable conditions.
Deflection during entry, zero while held still, then an opposite deflection during withdrawal. Faster motion increases the deflection.
Self-check · one mark per point
- Describe entry deflection from a changing field.
- Describe zero reading when stationary.
- Describe opposite withdrawal deflection.
- Link faster motion with greater deflection.
Common mistakes & how to avoid them
- Saying an ordinary transformer continuously transfers power from a steady d.c. supply. A changing magnetic field is needed to induce an e.m.f. in the secondary; switching can produce a temporary response, but a steady field cannot maintain it.
- Fleming's left-hand rule with the wrong hand or the wrong finger assignments: First finger = Field, seCond = Current, thuMb = Motion. Left hand for motors; the right hand belongs to generators.
- Induction answers without 'cutting field lines' or 'changing field'. Moving parallel to the field induces nothing — the conductor must cut lines.
- Mixing the motor and generator hardware: a d.c. motor uses a split-ring commutator (reverses current every half turn to keep it spinning one way); an a.c. generator uses slip rings.
- Transmission answers without the chain: high voltage → same power at lower current → less energy lost as heat in the cables (P = I²R).
Understand the why
Questions, explained
Start with the short answer, then follow the reasoning. Each explanation has a permanent link you can share with a classmate or return to when revising.
How do you increase the e.m.f. induced in a coil?
A larger induced e.m.f. results from a faster change in the magnetic field linked with a coil. In comparable arrangements, move the magnet faster, use a stronger magnet or increase the coil’s turns. An induced current additionally requires a complete conducting circuit.
A magnet’s mere presence is insufficient: holding it still relative to an unchanged coil does not continuously induce an e.m.f. Compare the rate of change rather than only the final field strength. In a practical investigation, keep the magnet path, coil and meter arrangement consistent while changing one variable. Increasing turns can also increase the coil’s resistance, so a change in meter current is not a pure measure of e.m.f. unless that effect is considered. Separate the induced voltage from the current it drives.
Why is electricity transmitted at high voltage?
For a given transmitted power, increasing voltage reduces current because P = IV. Lower current reduces resistive heating in cables according to P_loss = I²R. Transformers make that voltage change possible in an a.c. system; they do not create extra energy.
The cable resistance refers to the transmission path, while the desired transmitted power refers to the useful electrical transfer being delivered. Keep those quantities separate in the calculation. If current is halved and cable resistance remains constant, the heating loss becomes one quarter. Raising voltage brings its own insulation and design requirements, so the explanation is a reason for using high voltage rather than a claim that voltage can increase without limit. An ideal transformer preserves power; real equipment has additional losses.
Compare cable losses
A cable has resistance 2 Ω. Compare its heating loss at 10 A and 5 A.
- At 10 A: P_loss = 10² × 2 = 200 W.
- At 5 A: P_loss = 5² × 2 = 50 W.
Halving current reduces the heating loss to one quarter.
What is the difference between a split-ring commutator and slip rings?
A split-ring commutator swaps the coil’s connections every half-turn, allowing a simple d.c. motor to keep its turning effect in one direction. Slip rings maintain each coil end’s connection continuously, allowing a simple a.c. generator’s alternating e.m.f. to reach the external circuit.
The hardware should be matched to its purpose rather than memorised as two interchangeable rings. A motor’s coil rotates through positions where the same unaltered current direction would reverse its turning tendency, so commutation changes the coil current at the appropriate points. In the basic a.c. generator, rotation naturally reverses the induced e.m.f. every half-turn and the slip rings preserve that alternating output. Brushes provide contact with the rotating parts in both models. More complex machines exist, but the standard diagrams have these distinct functions.
Why does a transformer not work continuously on steady d.c.?
A steady direct current creates a steady magnetic field after switching transients, so it cannot maintain an induced e.m.f. in a transformer’s secondary. An alternating current continually changes the field. Switching a d.c. circuit can produce a brief response, which is different from sustained operation.
Induction depends on changing magnetic linkage, not simply on current existing in the primary. At the instant a switch closes or opens, the current changes, so the field can change and induce a secondary signal. Once an idealised steady current is established, that mechanism ceases. Do not claim that only sinusoidal current can ever induce a voltage: other changing waveforms can do so too. The syllabus transformer explanation uses a.c. because it supplies repeated field changes while supporting the stated voltage-ratio model.
What happens to induced current when the magnet’s motion is reversed?
Reversing a magnet’s motion relative to a coil reverses the change in magnetic linkage and therefore reverses the induced e.m.f. Reversing the pole orientation also reverses it. Reversing both together restores the original direction in an otherwise matching arrangement.
Describe one controlled change at a time. A north pole approaching a coil and the same north pole receding create opposite changes, so a centre-zero meter deflects in opposite directions. A stationary magnet produces no steady induced signal in this setup. Lenz’s law connects the direction to opposition to the change: the induced effect resists the process that produces it, consistent with needing mechanical work to generate electrical energy. The rule does not mean the induced field must always oppose the original field itself; it opposes the change.
Predict three meter readings
A north pole is pushed into a coil, held still and withdrawn at a comparable speed. Describe the sequence.
- Entry: deflection to one side because linked field changes.
- Held still: return to zero in the steady setup.
- Withdrawal: opposite deflection because the change reverses.
One-sided deflection, zero, then an opposite-sided deflection.
What happens to motor force if both current and field are reversed?
Reversing either current or magnetic field reverses the motor-effect force on a wire. Reversing both leaves the force direction unchanged. Apply the force-direction rule using conventional current, and keep the field, current and force directions distinct.
For a conductor perpendicular to the field, Fleming’s left-hand rule links three mutually perpendicular directions. Electron drift in a metal is opposite to conventional current, so using the electron direction without correcting it reverses the predicted answer. If the wire is parallel to the field, the magnetic force from this arrangement is zero rather than a force along the wire. When a diagram has several arrows, label their meanings before applying the rule; a motion arrow is not automatically the current direction.
Your learning checklist
Use these goals to check your understanding. Requirements vary by specification, tier and exam year; the official references below define your full course.
- Describe electromagnetic induction: an e.m.f. is induced when a conductor cuts field lines or the field through a circuit changes
- State the factors affecting the size of an induced e.m.f.
- Describe the a.c. generator with slip rings
- Describe the motor effect and use Fleming's left-hand rule
- Explain the turning effect on a current-carrying coil — the d.c. motor with split-ring commutator
- Describe the transformer: Vp/Vs = Np/Ns, and why high voltage is used for transmission
Sources & how to cite these notes
Original explanations, illustrations and practice by Dr Desouky Physics Academy. Official specifications guide the course scope; questions and suggested marks on this page are our own revision material.
- Cambridge IGCSE Physics 0625 — 2026–2028 syllabus
- Pearson Edexcel International GCSE Physics 4PH1 — specification
Reference this page
Dr Desouky Physics Academy. IGCSE Physics: Electromagnetic effects. Updated 2026-09-25. https://www.drdesouky.com/revision/igcse-physics/electromagnetic-effects
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