Edexcel IAL Physics revision · A2 — Mechanics & fields
Oscillations
Simple harmonic motion: the definition is an equation, and the examiner wants it with the minus sign explained. Everything else — energy interchange, damping, resonance — follows from that one line.
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What the syllabus demands
- —Define simple harmonic motion: a = −ω²x
- —Use x = x₀ sin ωt, v = ±ω√(x₀² − x²), and v_max = ωx₀
- —Describe the interchange between kinetic and potential energy in SHM
- —Describe light, critical and heavy damping
- —Describe forced oscillations and resonance; sketch amplitude-frequency curves
Definitions that earn marks
Clear definitions to practise — check your course mark scheme
- Simple harmonic motion
- Motion in which the acceleration is proportional to the displacement from a fixed point and always directed towards that point: a = −ω²x.
- Damping
- The removal of energy from an oscillating system by resistive forces, causing the amplitude to decrease over time.
- Resonance
- The condition in which a system oscillates with maximum amplitude, occurring when the driving frequency equals the natural frequency of the system.
The equations
More equations to practise: the Edexcel IAL formula sheet.
Where the marks die
Common mistakes to check
- 01
Defining SHM without both conditions: acceleration proportional to displacement AND directed towards the equilibrium position (the meaning of the minus sign). One without the other loses the mark.
- 02
Maximum speed placed at the extremes. Speed is maximum at the centre (x = 0); acceleration is maximum at the extremes (x = ±x₀). They are out of phase by 90°.
- 03
Claiming damping changes the frequency dramatically. Light damping reduces amplitude steadily but leaves the period almost unchanged — and shifts the resonance peak only slightly (to a lower frequency, with a lower, broader peak).
- 04
Resonance answers without 'natural frequency'. The mark scheme wants: driving frequency = natural frequency, maximum energy transfer, maximum amplitude.
One worked example, done properly
Question
A mass oscillates in SHM with amplitude 5.0 cm and period 2.0 s. Find its maximum speed and its speed at x = 3.0 cm.
Method
- 1.ω = 2π/T = π rad/s.
- 2.v_max = ωx₀ = π × 0.050 = 0.157 m/s.
- 3.At x = 0.030 m: v = ω√(x₀² − x²) = π√(0.0025 − 0.0009) = π × 0.040.
v_max ≈ 0.16 m/s; v ≈ 0.13 m/s at x = 3.0 cm