IGCSE Physics revision

IGCSE Physics revision · Thermal physics

Thermal properties of matter

Home of the two most misused ideas on the paper: specific heat capacity and the difference between boiling and evaporation. The calculation is routine; the marks die in the explanations.

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What the syllabus demands

  • Describe thermal expansion of solids, liquids and gases and its applications
  • Define specific heat capacity and use E = mcΔθ
  • Describe melting and boiling in terms of energy input without temperature change
  • Distinguish boiling from evaporation
  • Explain the factors that affect the rate of evaporation and its cooling effect

Definitions that earn marks

Clear definitions to practise — check your course mark scheme

Specific heat capacity
The energy required to raise the temperature of 1 kg of a substance by 1 °C.
Melting point
The temperature at which a solid changes to a liquid, with no temperature change while the change of state occurs.
Evaporation
The escape of the most energetic particles from the surface of a liquid, at any temperature below boiling — leaving the remaining liquid cooler.

The equations

Thermal energyE = m × c × Δθ · J

More equations to practise: the IGCSE formula sheet.

Where the marks die

Common mistakes to check

  1. 01

    Using the full temperature instead of the temperature change in E = mcΔθ. It is Δθ — final minus initial.

  2. 02

    Saying temperature rises during melting or boiling. It does not: the energy input goes into breaking bonds between particles (increasing potential energy), not into raising temperature. Flat sections on a heating curve are worth marks only if you say why.

  3. 03

    Confusing evaporation with boiling. Boiling happens at one temperature, throughout the liquid, with bubbles. Evaporation happens at any temperature, only at the surface.

  4. 04

    Explaining evaporation's cooling effect without 'most energetic': the fastest particles escape, so the average kinetic energy of those remaining falls — and average kinetic energy is temperature.

One worked example, done properly

Question

How much energy is needed to heat 2.0 kg of water from 20 °C to 70 °C? (c of water = 4200 J/(kg °C))

Method

  1. 1.Δθ = 70 − 20 = 50 °C.
  2. 2.E = mcΔθ = 2.0 × 4200 × 50.

E = 420,000 J = 420 kJ

Fit these topics into your free physics revision plan

Common questions

Asked, answered.

Why does temperature stay constant during melting?

The energy supplied is used to break the bonds between particles (increasing their potential energy) rather than to increase their kinetic energy — and temperature measures average kinetic energy. Once the change of state is complete, the temperature rises again.

Why does evaporation cool a liquid?

Only the most energetic particles have enough energy to escape from the surface. When they leave, the average kinetic energy of the remaining particles decreases — and lower average kinetic energy means lower temperature.

What factors increase the rate of evaporation?

Higher temperature, larger surface area, and air movement (draught) across the surface. Each factor is a separate mark in the standard question.

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